Question

In given figure O is centre of the circle if angle AOC is equal 130 degree the figure angle abc

Answer 1

if angle AOC=130°
then angle AOB=360-130=230°

Answer 2

Answer:

Step-by-step explanation:

Draw a circle O and AB diameter of circle

draw a point C on the circle making ∠AOC= 130 °

Now draw lines AC and BC

Here AC⊥BC

Here AO = OC

Therefore, ∠OAC=∠OCA

In ΔAOC, AO= OC= radius of circle

∠AOC+∠OCA+∠OAC= 180

∠OCA+∠OAC= 180-130=50

∠OAC= 25°

In ΔABC ,

∠ABC= 180-90-25=65°