Question

In given figure O is the centre of a circle if the area of the Sector No APB is 5 upon 36 times the area of the circle then find the value of x

Answer 1

Value of x = 50

Step-by-step explanation:

Area of a sector  = ( Sector Angle / 360) π r²

Area of the sector   = ( 5/36 )Area of the circle

Area of the circle = π r²

Area of the sector   =  ( 5/36 ) π r²

Sector Angle = x

=> Area of a sector   =  (x / 360) π r²

Equating both

=> (x / 360) π r² =  ( 5/36 ) π r²

=> x/360 = 5/36

=> x = 50

Value of x = 50

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