Question

In given figure, PA and PB are tangents to a circle drawn from an external

point P. CD is the third tangent touching the circle at Q. if PA = 15 cm find the

perimeter of ∆PCD.​

Answer 1

Step-by-step explanation:

∵PA and PB are tangent from same external point 

∴PA=PB=15cm

Now, perimeter of ΔPCD=PC+CD+DP=PC+CQ+QD+DP

=PC+CA+DB+DP

=PA+PB=15+15=30cm