in given figure prove that angle ADC is equal to angle A + Angle B + angle C
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Answer is in the attachment below
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Ojasvisahu:
Thanks bro
Answered by
69
Answer:
The proof is explained below.
Step-by-step explanation:
In the given figure ABCD, we have to prove that
∠A+∠B+∠C=∠ADC
Let us do construction: Join BD
In ΔABD,
By exterior angle property which states that an exterior angle of triangle is equal to the sum of opposite interior angles i.e
∠1+∠2=∠5 → (1)
Similarly in ΔCBD
∠4+∠3=∠6 → (2)
Adding equation (1)a nd (2), we get
∠1+∠2+∠4+∠3= ∠5 +∠6
⇒ ∠1+(∠2+∠3)+∠4=∠ADC
⇒ ∠A+∠B+∠C=∠ADC
Hence proved.
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