In given figure, PS is the diameter of a circle of radius 6 cm. The points Q and R trisects the diameter PS. Semi circles are drawn on PQ and QS as diameters. Find the area of the shaded region.
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Solution is in the following image..
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sivakrishnaoftotlqzt:
ur answer is very easy to understand .Thank u
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┏─━─━─━─━∞◆∞━─━─━─━─┓
✭✮ӇЄƦЄ ƖƧ ƳƠƲƦ ƛƝƧƜЄƦ✮✭
┗─━─━─━─━∞◆∞━─━─━─━─┛
PS = 12 cm (6+6)
As PQ = QR = RS
➧ PQ = QR = RS
➾ 1/3 × PS
➾ 1/3 × 12
➾ 4 cm
QS = 2 PQ
QS = 2 × 4
= 8 cm
➧ Area of shaded region =
Area of semicircle with PS as diameter + Area of semicircle with PQ as diameter - Area of semicircle with QS as diameter.
➾ ½ [3.14 × 6² + 3.14 × 2² - 3.14 × 4²]
➾ ½ [3.14 × 36 + 3.14 × 4 - 3.14 × 16]
➾ ½ [3.14 (36 + 4 - 16)]
➾ ½ (3.14 × 24) = ½ × 75.36
➧ Area of shaded region,
➾ 37.68 cm²
_________
Thanks...✊
✭✮ӇЄƦЄ ƖƧ ƳƠƲƦ ƛƝƧƜЄƦ✮✭
┗─━─━─━─━∞◆∞━─━─━─━─┛
PS = 12 cm (6+6)
As PQ = QR = RS
➧ PQ = QR = RS
➾ 1/3 × PS
➾ 1/3 × 12
➾ 4 cm
QS = 2 PQ
QS = 2 × 4
= 8 cm
➧ Area of shaded region =
Area of semicircle with PS as diameter + Area of semicircle with PQ as diameter - Area of semicircle with QS as diameter.
➾ ½ [3.14 × 6² + 3.14 × 2² - 3.14 × 4²]
➾ ½ [3.14 × 36 + 3.14 × 4 - 3.14 × 16]
➾ ½ [3.14 (36 + 4 - 16)]
➾ ½ (3.14 × 24) = ½ × 75.36
➧ Area of shaded region,
➾ 37.68 cm²
_________
Thanks...✊
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