Question

in given figure QTand RT bisector of angle QandR find a b c d with measure of 80 and 30​

Answer 1

Answer:

in parallelogram ∠R+∠Q=180 o

but ∠1=∠2 and ∠3=∠4 [given]

⇒∠1+∠2+∠3+∠4=180 o

∴∠1+∠3=90 o

∴∠T=180−90 o=90 o  proved  [sum of angles in a triangle=180 o]

Step-by-step explanation: