In given figure show that AB //BC
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In figure
angle DFI = 100. ... (opposite angle of JFH)
angle GIE = 45. ... (opposite angle of FIH)
IN triangle GIE
angle GIE + angle IGE +angle GEI=180
45+55+angle GEI=180
angle GEI =80
angle GEI +angle DFI
=100+80
=180
SO line AB//line CD.... ( alternate angles test)
angle DFI = 100. ... (opposite angle of JFH)
angle GIE = 45. ... (opposite angle of FIH)
IN triangle GIE
angle GIE + angle IGE +angle GEI=180
45+55+angle GEI=180
angle GEI =80
angle GEI +angle DFI
=100+80
=180
SO line AB//line CD.... ( alternate angles test)
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