Question

in given figure show that r = ar(abc) / semi perimeter​

Answer 1

Answer:

Given below

Step-by-step explanation:

Let I be the incenter of △ABC.

Let r be the inradius of △ABC.

The total area of △ABC is equal to the sum of the areas of the triangle formed by the vertices of △ABC and its incenter:

A=Area(△AIB)+Area(△BIC)+Area(△CIA)

Let AB, BC and CA be the bases of △AIB,△BIC,△CIA respectively.

The lengths of AB, BC and CA respectively are c,a,b.

The altitude of each of these triangles is r.

Thus from Area of Triangle in Terms of Side and Altitude:

Area(△AIB) =    cr/2    

Area(△BIC) =    ar/2    

Area(△CIA) =    br/2    

Thus:

A=r{a+b+c}/2

That is:

A=rs

r= Area (ABC)/s

where s=(a+b+c)/2 is the semiperimeter of △ABC.

Please mark my answer as the brainliest

Answer 2

Answer:

where is the figure ????