In given figure, sides QP and RQ to PQR are extended upto points S and T. If angle SPQ = 135 degree, angle PQR = 110 degree find angle PRQ
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3
Answer:
∠PQT+∠PQR=180
∘
(Straight angle made on line TR at point Q)
110
∘
+∠PQR=180
∘
∠PQR=180
∘
−110
∘
=70
∘
In △PQR
∠PSR=∠PQR+∠PRQ (Exterior angle of triangle is eqal to sum of two interior angles)
135
∘
=70
∘
+∠PRQ
∠PRQ=135
∘
−70
∘
=65
Answered by
54
Answer:
65°
Step-by-step explanation:
refer the attachment
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