Question

In given figure, ST II RQ, PS = 3 cm and SR = 4 cm. Find the ratio of the area of ΔPST to the area of ΔPRQ.

Answer 1

the ratio of the area of triangle PST to traingle PRQ is 9:16 by the theorem of areas of similar triangles

Answer 2

Answer:

9:49

Step-by-step explanation:

Given

ST || RQ

PS= 3 cm

SR = 4cm

Proof :--

ar(∆PST) /ar(∆PRQ) = (PS)²/(PR)²

ar(∆PST) /ar(∆PRQ) = 3²/(PS+SR)²

ar(∆PST) /ar(∆PRQ) = 9/(3+4)²= 9/7² = 9/49

Hence, the required ratio ar(∆PST) :ar(∆PRQ) = 9:49