Question

In given figure St parallel RQ, PS is equal to 3 cm and ac is equal to 4 cm find the ratio of the area of area of triangle PST to the area of triangle prq

Answer 1

THEOREM - the ratio of the areas of two similar triangle is equal to the square of there corresponding side

so, (area of triangle pst)^2/(area of triangle abc)^2=3^2/4^2

                                                                                      =9/16 ans