Question

IN GIVEN FIGURE ST PARALLEL TO RQ , PS = 3 CM AND SR = 4 CM. FIND THE RATIO OF TRIANGLE PST TO THE AREA OF TRIANGLE PRQ

Answer 1

Given:

ST || RQ

PS= 3 cm

SR = 4cm

We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides.

ar(∆PST) /ar(∆PRQ)= (PS)²/(PR)²

ar(∆PST) /ar(∆PRQ)= 3²/(PS+SR)²

ar(∆PST) /ar(∆PRQ)= 9/(3+4)²= 9/7²=9/49

Hence, the required ratio ar(∆PST) :ar(∆PRQ)= 9:49

Answer 2

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