Question

In given figure, the sides AB and AC of ∆ ABC are produced to points E and D

respectively. If bisectors BO and CO of ∠ CBE and ∠ BCD respectively meet at point O,

then prove that ∠ BOC = 90° – 1/2 ∠ BAC.​

Answer 1

Refer The Attachment ⬆️

$\red{\sf{@MrMonarque}}$

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