In given figure three lines ab cd and ef intersecting at O. Find the value of xyz and is beginning given that 2:3:5
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2
X+Y+Z=2+3+5=10,X°=2/10×180=2×18=36°,Y°=3/10×180=3×18=54°,Y°=54°,Z°=5/10×180=5×18=90°,Z=90°
X,Y,Z=36°,54°,90°
Answered by
10
Thank you for asking this question. Here is your answer:
angle DOB= z
angle AOE= x
angle COF= y
therefore x+x+y+y+z+z=360°
2(x+y+z)=360
x+y+z=180____________(2)
x:y:z= 2:3:5
x= 2k , y= 3k , z= 5k _____(1)
substituting(1) in (2)
2k+3k+5k=180
10k=180
k=18
therefore
x=2×18=36°
y=3×18=54°
z=5×18=90°
If there is any confusion please leave a comment below.
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