Math, asked by sanzimetharath5933, 1 year ago

In given figure three lines ab cd and ef intersecting at O. Find the value of xyz and is beginning given that 2:3:5

Answers

Answered by budumuru74
2

X+Y+Z=2+3+5=10,X°=2/10×180=2×18=36°,Y°=3/10×180=3×18=54°,Y°=54°,Z°=5/10×180=5×18=90°,Z=90°

X,Y,Z=36°,54°,90°

Answered by Shaizakincsem
10

Thank you for asking this question. Here is your answer:

angle DOB= z

angle AOE= x

angle COF= y


therefore x+x+y+y+z+z=360°

2(x+y+z)=360

x+y+z=180____________(2)


x:y:z= 2:3:5

x= 2k , y= 3k , z= 5k _____(1)

substituting(1) in (2)

2k+3k+5k=180

10k=180

k=18


therefore

x=2×18=36°

y=3×18=54°

z=5×18=90°


If there is any confusion please leave a comment below.

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