In given network as shown in figure current 1 A and 2 A flow across 6 and 3 ohm resistance the internal resistance of battery is
Answers
Answer:
The current through the 2Ω resistor is 3.0 A. What is the E.M.F. of the battery?
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OK this is a school problem so no complete answer but only hints.
If the current flowing through that resistor is 3A , it means that the voltage drop across it (Ohm Law) is VAB=R⋅I=2⋅3=6V .
All the three paralleled resistors have the same voltage drop, therefore we can compute the current flowing through the other ones and, summing them up, the total current flowing from B to A through these resistors.
Now, if you see the circuit as the EMF generator, the 6Ω resistor and the parallel of the three resistors, you can compute the current flowing through the circuit itself.
What is the current through the 3.0Ω resistor?
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A battery of 9V is connected in a series with resistors of 0.2ohm, 0.3ohm, 0.4ohm, 0.5ohm and 12ohm. How much current would flow through the 12ohm resistor?
A battery of an emf of 12 V and internal resistance of 5 Ω is connected to a resistor. If the current through the circuit is 0.3 A, what is the resistance of the resistor? What is the terminal voltage of the battery when the circuit is closed?
A battery of emf 10 V and an internal resistance of 3 Ohm is connected to a resistor. If the current in the circuit is 0.5 A, what is the resistance of the resistor?
Since the current through the 2Ω resistor is 3.0A , the potential difference across this resistor, by Ohm’s law, is 2Ω×3.0A=6.0V . Since the 6.0Ω , and the 3.0Ω resistors are in parallel with the 2.0Ω resistor, the potential difference across the 6.0Ω , and the 3.0Ω resistors is also 6.0V . Then,the current through the 6.0ω resistor is 6.0V6.0Ω=1.0A , and that through the 3.0ω resistor is 6.0V3.0Ω=2.0A . So, the current in the circuit is (1.0+2.0+3.0)A=6.0A . The potential difference across the other 6.0Ω resistor is 6.0A×6.0Ω=36.0V . The total potential difference in the circuit is thus, (36.0+6.0)V=42.0V . So, the supplied potential difference is 42.0V .