Question

in given triangle
line pq parallel to rs and find a b c d with measure of 70 and 100​

Answer 1

Answer:

PQ||RS (GIVEN)

PAB=70°

ACS=100°

TO DETERMINE ANGLE ABC,BAC and CAQ

1. FOR ABC

ACS=ABC=100°(CORRESPONDING ANGLES)

2.FOR BAC

ABC+BCA+CAB=180°(ANGLE SUM PROP.OF A TRIANGLE)

100°+BCA+70°=180°

170°+BCA=180°

BCA=180°-170°

BCA=10°

3.FOR CAQ

A=Q=70°(CORRESPONDING ANGLES)

HOPE IT HELPS YOU

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