Question

in go the 9th term is 32805and 6th term is 1215. find the 12th term
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Answer 1

Answer:

a9=32805

a6=1215

a12=?

Step-by-step explanation:

a+8d=32508---1

a+5d=1215-----2

3d=31293

d=31293/3

d=10431

put in 1 eq

a+8*10431=32508

a+83448=32508

a=32508-83448

a=50940

a+11d

50940+11*10432

a12=165681

hope its helpful

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Answer 2

Answer:

we need to find a and d for the 12th term

a+8d=32805

eq. no.1

a+5d=1215

eq. no.2

by elimination method

a+8d=32805

a+5d=1215

(- )(-) (-)

3d=31590

d=31590/3

=10530

put the value of d in eq.1

a+8×10530=32805

a=32805-84240

a= - 51435

a+11d=

-51435+11×10530

-51435+115830

64395

the 12th term is 64395