Question

in godavari express, there are as many wagons as there are seats in each wagon and not more than one paswnger can have the same berth (seat). if the middle most compartment carrying 25 passengers is filled with 71.428% of its capacity , then find the maximum no of passengers in the train that can be accommodated if it has minimum 20% seats are vacant

Answer 1

Hi friend,

Given,

25 passengers are equal to 71.428% of total capacity of wagon.

Means, 71.428% passengers = 25.

1% passengers = 25/71.428

Hence, 100% passengers = (25*100)/71.428 = 35 passengers.

Capacity of one wagon = 35.

So, number of wagon = 35.

Total capacity of the train = 35 *35 = 1225.

Also, given 20% seat remains vacant.

Thus, the number of passengers in the train,

= 1225 - 20% of 1225 = 1225 - 245 = 980.


HOPE THIS HELPS YOU:-))

Answer 2

given 25 passengers = 71.428%

         ∴   100 % = 25x100/71.428
                       = 35

 Therefore there are 35 wagons and 35 passengers in each wagon, 

Maximum no of passengers in the train that can be accommodated if it has minimum 20% seats = 35x35x80/100 
                                   = 980