In Gp if a=1/2,r=1/3, then S6=?
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Answer:
your answer is 182\243
Step-by-step explanation:
in g..p. a=1\2 and r=1\3
in g.p. r=less than one. so we take the formyla of sum
sn: [a(1-r^n)]÷[1-r)
a=1\2 ,r=1\3 and n=6
:[1\2{1-(1\3)^6}]÷[1-(1\3)]
:[1\2{1-(1\729)]÷[2\3]
:[1\2{728\729}]×[2\3]
:[1\2×{3\2}×{728\729}]
:[546÷729]=(182×3)÷(243×3)
:182\243
answer is 182\243
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