In GP the 3rd term is 24 and 65th term is 192.Find the 10th term
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Step-by-step explanation:
we know that an = ar^n-1.
Given that 3rd term is 24
a3 = ar^2 = 24 (1)
Given that 6th term is 192
a6 = ar^5 = 192 (2)
On dividing (2) by (1), we get
r^3 = 8
r = 2 --- (3).
Substitute (3) in (1), we get
a * (2)^2 = 24
4a = 24
a = 6.
The 10 th term a10 = 6 * (2)^9
= 3072.
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