Math, asked by kamleshgupta, 1 year ago

in GP.., the 3rd term is 24 and the 6th term is 192. find 10th term.

Answers

Answered by deepsinghrajput
1
a=6
r=2
10 th term =a*r^9
Answered by Redman
0
Let 3rd term be ax
Let 6th term be ax(x^3)
Let 9th term be ax^7
So,
ax=24
ax(x^3)=192
So,x^3=8
Then x=2
Then a=3
So,ax^7=3*128=384
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