Question

in GP the third term is 24 and 6 term is 192 find the 10th term

Answer 1

a3=24
a6=192
a+2d=24
a+5d=192
on solving we get
-3d=-168
d=56
then the value a is
a+2×56=24
a+112=24
a=-88
then the 10th term is
a+(n-1)d
-88+(10-1)56
-88+504
416 is the answer
I hope its helpful for you