Question

in group of students, 50 passed in enlish,60 passed in maths and 40 students passed in both .find the number of students passed either english or in maths?​

Answer 1

Step-by-step explanation:

, n(A∪B)=n(A)+n(B)−n(A∩B) , hence 50+60-40=70 is the Answer

Answer 2

Answer:

70

Step-by-step explanation:

here n(A) =60,n(B)=50

n( A∩B)=40

now n(A∪B)=n(A)+n(B)−n(A∩B) , we have

Number of students who passed either in English or Math =60+50−40=70