Question

In H-atom electron jumps from 3rd to 2nd energy level, the energy released is..

Answer 1

Answer:

In H-atom electron jumps from 3rd to 2nd energy level.

Explanation:

energy of an electron: E = -13.6 (Z^2 / n^2)

here n = principal quantum no.

and z = atomic no.

E = -13.6 (1/ n^2) J

energy released when electron jumps from n = 3 to n = 2 is the difference in energy between the orbits

so Energy released = -13.6 (1/4 - 1/9 ) J

= -13.6 (5/36) J

= 2 J

Answer 2

Answer:

1.89eV

Explanation:

ENERGY DIFFERENCE BETWEEN TWO ENERGY LEVEL :

En₂-En₁ = -13.6 ˣ Z² [1/ ₍n₂₎²- 1/₍n₁₎²]

E₃ - E₂ = -13.6 ˣ Z² [1/₍₃₎²₋1/₍₂₎²]

          = -13.6 ˣ ( -5/36) = 1.89 eV

1eV = 1.6 ˣ 10⁻¹⁹ J

so, E₃ -E₂ = 1.89 ˣ 1.6 ˣ10⁻¹⁹ J = 3.03 ˣ 10⁻¹⁹ J