Math, asked by dilipreddy881, 1 year ago

In H.p the 3rd term is 1/7 and 7 th term is 1/5 then show that the 15 th term is 1​ plss solve

Answers

Answered by bhagyashreechowdhury
6

Given:

In H.P. the 3^r^d term is 1/7 and 7^t^h term is 1/5

To show:

The 15^t^h term is 1​

Solution:

We know the formula for the n^t^h term of an H.P. is:

\boxed{\bold{T_n \:of \:H.P. = \frac{1}{a + (n - 1)d} }}

According to the question, we get

t_3 =  \frac{1}{a + (3 - 1)d} }}

\implies \frac{1}{7}  =  \frac{1}{a + (3 - 1)d} }}

\implies \frac{1}{7}  =  \frac{1}{a + 2d}

\implies 7 = a + 2d

Also, we get

t_7 =  \frac{1}{a + (7 - 1)d} }}

\implies \frac{1}{5}  =  \frac{1}{a + (7 - 1)d} }}

\implies \frac{1}{5}  =  \frac{1}{a + 6d}

\implies 5 = a + 6d

On subtracting both the equations above, we get

a + 2d = 7

a + 6d = 5

-  -         -

-----------------

   -4d = 2

------------------

\bold{d = - \frac{1}{2}}

On substituting the value of d in one of the equation, we get

7 = a + (2\times \frac{-1}{2} )

\implies 7 = a -1

\implies a = 7 +1

\implies \bold{a = 8}

Now,

The 15^t^h term is,

= t_1_5

= \frac{1}{a + (15 - 1)d}

= \frac{1}{8 + (15 - 1)(\frac{-1}{2} )}

= \frac{1}{8 + (14)(\frac{-1}{2} )}

= \frac{1}{8 - 7}

= \boxed{\bold{1}}

-----------------------------------------------------------------------------------------

Also View:

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In a Harmonic Progression 4/3, 3/2, 12/7. find 7th term?

https://brainly.in/question/1095044

10th term of a Harmonic Progression is third and fifth terms are respectively 1 and 1 by -5​

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