Question

In h2-o2 fuel cell, 11.2l h2 at ntp reacts in 5000sec, the current(average) produced by the fuel cell is 1) 1.93 2) 19.3 3)9.65 4)96.5

Answer 1

Answer:

Explanation:

Applying Faraday 1st law

Q/F = mole×V.f.

It/F = (11.2/22.4) × 2

       =[(11.2 ×F) /(22.4 × 5000)] × 2

       = 19.297

   I   = 19.3 A

Answer 2

The current produced by the fuel cell is 19.3 A

Explanation:

We are given that:

• Quantity of H2 = 11.2 liter
• Time of reaction = 5000 seconds

To Find: The average current produced by the fuel cell.

Solution:

By using the Faraday's law.

Q/F = mole × V.f

We know that Q = I x t

I x t / F = [ 11.2 / 22.4 ] × 2

I = [ (11.2 × F) / (22.4 × 5000) ] × 2

I = [ 11.2 x F / 112,000 ] x 2

I = 19.297

I = 19.3 A

Hence, the current produced by the fuel cell is 19.3 A.