Question

In Haber's process 50.0 g of N2(g) and
10.0 g of H2(g) are mixed to produce NH3(g).
What is the number of moles of NH3(g)
formed?

1) 3.33 2) 2.36 3) 2.01 4) 5.36​

Answer 1

Answer:

Top answer

N2 + 3H2 2NH3 Moles of N2 = 5028 = 1.785 moles Moles of H2 = 102 = 5 moles 1 mole of N2 reacts with 3 moles H2 . H2 is limiting reagent.3 moles H2 form ... More