Physics, asked by pav08august, 8 months ago

In half wave plate, the phase difference between ordinary and extraordinary ray is :
pi pi/2 pi/4 3pi/2

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Answered by singhtimci
4

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Answered by Jaswindar9199
0

In half wave plate, the phase difference between ordinary and extraordinary ray is π.

  • A half wave plate is a thin plate of birefringent crystal having the optic axis parallel to its refracting faces.
  • It's thickness is chosen such that it introduces a path difference of lambda/2 or a phase difference of π (180°) between the ordinary ray and the extraordinary ray.

Phase difference = 2π × delta / lambda

Phase difference = 2π × delta / lambda = π = 180°.

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