In half wave rectifier if the D.C component at output is 10πV What is the peak value of sinusoidal input signal.
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hey mate here is your answer...
The output waveform v0 of a half wave rectifier consists of the positive pulses of the input signal, less a bit for the diode drop.
The DC component of that is defined as its average. That's the DC value that would appear after a while on the output of a lowpass filter connected to v0.
The RMS value of v0 is defined as the DC value that gives the equivalent heating in the load resistor.
The difference is small but significant for modestly rippling waveforms like this. There is no difference if v0 is DC. The difference increases as the waveform becomes more spiky.
One way to see what's happening, which I understand not everybody will grok, is that the RMS value of the waveform measures the total power that's available in all its components, AC and DC. The average value measures the power of only the DC component. The difference between the DC value and the RMS value will therefore be a measure of the power available in the non-DC components, that is the AC power of the waveform. This means that we can say that RMS≥averageDC, always.
If you were to connect a capacitor across the output resistor, it would hold the peak voltage of v0, which is larger than the RMS value of the input voltage vI, a fact that often confuses the uninitiated.
hope it helps you dear..
❤❤⭐⭐❤❤⭐⭐
The output waveform v0 of a half wave rectifier consists of the positive pulses of the input signal, less a bit for the diode drop.
The DC component of that is defined as its average. That's the DC value that would appear after a while on the output of a lowpass filter connected to v0.
The RMS value of v0 is defined as the DC value that gives the equivalent heating in the load resistor.
The difference is small but significant for modestly rippling waveforms like this. There is no difference if v0 is DC. The difference increases as the waveform becomes more spiky.
One way to see what's happening, which I understand not everybody will grok, is that the RMS value of the waveform measures the total power that's available in all its components, AC and DC. The average value measures the power of only the DC component. The difference between the DC value and the RMS value will therefore be a measure of the power available in the non-DC components, that is the AC power of the waveform. This means that we can say that RMS≥averageDC, always.
If you were to connect a capacitor across the output resistor, it would hold the peak voltage of v0, which is larger than the RMS value of the input voltage vI, a fact that often confuses the uninitiated.
hope it helps you dear..
❤❤⭐⭐❤❤⭐⭐
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