In hardly - Weinberg equation, the frequency of homogeneous recessive individual is represented by:-
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The Hardy-Weinberg equation is given by :
p² + 2pq + q² = 1
Here, p and q represent the individual allele frequencies.
Therefore, p² = frequency of homozygous condition represented by p.
q² = frequency of homozygous alleles represented by q.
and 2pq = frequency of heterozygous condition.
So, the correct answer is '2pq'
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