Biology, asked by DHARAMAHIR8507, 10 months ago

In hardy‒weinberg equation, the frequency of heterozygous individual is represented by


Anonymous: ___k off

Answers

Answered by Anonymous
0

The frequency of genotypes in a population can be represented by p2+2pq+q2= 1, with p2 equal to the frequency of the homozygous dominant genotype, 2pq equal to the frequency of the heterozygous genotype, and q2 equal to the frequency of the recessive genotype.

Answered by parth7b
4

Answer:

for heterozygous INDIVIDUAL = 2pq

Explanation:

NOTE that

"p" represents dominant ALLELE

"q" represents recessive ALLELE

(p+q=1)

BUT

"p^{2}" represents homozygous dominant INDIVIDUAL

"q^{2}" represents homozygous recessive INDIVIDUAL

and "2pq" represents heterozygous INDIVIDUAL

(p^{2} + q^{2} + 2pq = 1)

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