in hcf of 144 amd 180 is expressed in the form 13m-3 find the value of m
Answers
Answered by
1
Hey
Here is your answer,
144=2^4 × 3^2
180=2^2 × 3^2 ×5
HCF of 144 and 180 is (2^2 × 3^2)=36
Given HCF of 144 and 180 is 13m-3
36=13m-3
13m=36+3
13m=39
m=39/13
m=3
Hope it helps you!
Here is your answer,
144=2^4 × 3^2
180=2^2 × 3^2 ×5
HCF of 144 and 180 is (2^2 × 3^2)=36
Given HCF of 144 and 180 is 13m-3
36=13m-3
13m=36+3
13m=39
m=39/13
m=3
Hope it helps you!
Answered by
1
Heya !!!
Prime factorisation of 144 = 2 × 2 × 2 × 2 × 3 × 3
Prime factorisation of 180 = 2 × 2 × 3 × 3 × 5
HCF of 144 and 180 = 2 × 2 × 3 × 3 = 36
According to question,
HCF of 144 and 136 is expressed in the form of 13M - 3.
So,
13M - 3 = 36
M = 36+3/13
M = 39/13
M = 3
Hence,
Value of M is 3 .
★ HOPE IT WILL HELP YOU ★
Prime factorisation of 144 = 2 × 2 × 2 × 2 × 3 × 3
Prime factorisation of 180 = 2 × 2 × 3 × 3 × 5
HCF of 144 and 180 = 2 × 2 × 3 × 3 = 36
According to question,
HCF of 144 and 136 is expressed in the form of 13M - 3.
So,
13M - 3 = 36
M = 36+3/13
M = 39/13
M = 3
Hence,
Value of M is 3 .
★ HOPE IT WILL HELP YOU ★
Similar questions