Math, asked by atzoo, 5 months ago

in hcf of 65and 117 is expressible in the form 65n-117then find the value of n

Answers

Answered by vyshugarige

1

Answer:

2

Step-by-step explanation:

65=5×13

117=13×9

HCF=13

HCF=65n-117

13+117=65n

130=65n

n=2

hope it helps you

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