Question

In HCl, the transport number of H+ is
0.82, then the transport number of Cl-
is​

Answer 1

Answer:

Correct option is A)

Transport no. of H

+

ions=

1000Q

l×a×c

(moving boundary method)

l is length of migration =7.50cm

a is area of cross-section =1.24cm

2

c is concentration of solution =0.1N

Q is charge passed = Equivalent of Ag deposited

=

108

0.1209

Faraday(Q=

E

W

)

∴t

H

+

=

0.1209×1000

7.5×1.24×0.1×108

=0.8308

Transport no. of H

+

ions is 0.8308

Thus the correct answer is 10×(0.8308)=8.308≈8

Now, t

H

+

+t

Cl

−

=1

∴t

Cl

−

=1−0.8308=0.1692

Transport no. of Cl

−

ions is 0.1692.

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