Question

in head on collision a 12 KG ball moving with a velocity of 25 metre per second collides with another ball of 4 kg initially at rest after collision the speed of the 12 KG ball is reduced to 19 per second the speed of the 4 kg ball will be

Answer 1

this will be answer may be

Answer 2

The final speed of 4 kg ball will be 18 m/s.

Explanation:

Given that,

Mass 1, $m_1=12\ kg$

Initial speed of first ball, $u_1=25\ m/s$

Mass 2, $m_2=4\ kg$

Initial speed of second ball, $u_2=0$ (at rest)

After the collision,

Final speed of mass 1 is reduced to 19 per second, $v_1=19\ m/s$

We need to find the final speed of mass 2. Using the conservation of momentum as :

$m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\\v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}\\\\v_2=\dfrac{12\times 25+0-12\times 19}{4}\\\\v_2=18\ m/s$

So, the final speed of 4 kg ball will be 18 m/s.

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