Question

In hot water heating system, there is a cylindrical pipe of length 28m and diameter 5 cm. Find the total radiating surface in the system.

Answer 1

length of the cylindrical pipe = 28m

diameter = 5cm

radius = 5/2cm = 2.5cm = 0 .025m.

total radiating surface of cylindrical pipe = CSA of a cylinder.

CSA of Cylinder =
$2\pi \: r \: h$

= 2 × 22/7 × 0.025 × 28

= 4.4 m^2.

Answer 2

Given:-

• A cylindrical pipe of length 28m and diameter 5 cm.

To find:-

• Find the total radiating surface in the system.

Solutions:-

• length = 28m
• Diameter = 5cm

The height of the cylinder is in metars.

• Let us first convert in into centimetres.

h = 2800cm

Also,

the diameter of the cylinder

r = diameter/2

r = 5/2

The total surface area = 2πrh + 2πr²

= 2 × 22/7 × 5/2 × 2800 + 2 × 22/7 × 5/2 × 5/2

= 22 × 5 × 400 + 11/7 × 5 × 5

= 110 × 400 × 11/7 × 25

= 4400 + 39.28

= 44039.28cm²

Hence, the total surface area of cylinder is 44039.28cm².

Some Important:-

Volume of cylinder ( Area of base × height ).

= (πr²) × h

= πr²h

Curved surface = ( Perimeter of base ) × height.

= (2πr) × h

= 2πrh

Total surface are = Area of circular ends + curved surface area.

= 2πr² + 2πrh

= 2πr(r + h)

Where, r = radius of the circular base of the cylinder.

h = height of cylinder.