Question

in household during a particular week three 2kw fires are used on every 25 hour each and 100 watt light bulb are used on average 35 hours each determine the cost of electricity for the week is 1 unit of electricity cost 7 paisa​

Answer 1

3 fire = 2kw ×3 = 6kw power

Time = 25h × 7 = 175 h

power = 6 × 175 = 1050u

cost for 1 week = 7 ×1050 = 7350p

light bulb = 100w = 0.1 kw

time =35 h ×7 = 245

power of bulb = 245 × 0 .1 kw = 24.5 u

cost for 1 week = 7 × 24.5 = 171.5 p

Answer 2

Answer:

The total price of electricity will be $2670$.

Explanation:

$E = P*(t/1000)$ ; where $E$ Joules or kilowatt-hours ($kWh$) are used to measure energy, $P$ power is measured in watts, and $t$ is the amount of time that power or energy is consumed. Therefore, whenever someone asks you how to calculate power consumption, you may compute and respond using the aforementioned equation.

First, a calculation and statement of the quantity of energy used are $kWh$,

The usage of a lightbulb will be $100 W=0.100 kW$.

Power $=$ $3$ fires $*$ $2$ fire/$kW$$* 25$ hours

and $8$ bulbs $* 0.100$ bulb/$kW$ $*35$ hours.

Energy used $= (6.25 + 7.4) kWh$

$= (150 + 28) kWh = 178 kWh$

After that, we can calculate the overall cost by simply multiplying two components:

$178 kWh$ at a cost of $15$ per $kWh$ is $2670$ pence.

Consequently, the overall cost of power will be $2670$.

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