Question

in how many 3 digit numericals 8 appear only once​

Answer 1

Answer:

To find the total three digit number in which 8 will appear only once

CASE 1: the total three digit number in which 8 will appear on unit place only = 8*9*1=72

CASE 2: the total three digit number in which 8 will appear on ten place only = 8*1*9=72

CASE 3: the total three digit number in which 8 will appear on hundred place only = 1*9*9=81

SO, the total three digit number in which 8 will appear only once=72+72+81=225

To find the total three digit number in which 8 will appear two times

CASE 1: the total three digit number in which 8 will appear on unit place and ten place =8*1*1=8

CASE 2: the total three digit number in which 8 will appear on unit place and hundred place =1*9*1=9

CASE 3: the total three digit number in which 8 will appear on ten place and hundred place =1*1*9=9

SO,the total three digit number in which 8 will appear two times=8+9+9=26

the total three digit number in which 8 will appear all three times=1*1*1=1

Now no of times 8 will appear in three digit number=225+2*26+3*1=225+52+3=280

Step-by-step explanation:

plz mark me as brainiest and follow main

Answer 2

Answer:

108,208,308,408,508,608,708,908

180,280,380,480,580,680,780,980

801,802,803,804,805,806,807,809

800