In how many cases should we expect to get 6 heads and 4 tails .if 10 coins are simultaneously tossed 1000 times?
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Answer:
205.08
Step-by-step explanation:
This example is related to binomial distribution
Let p be the probability of head and q be the probability of tail
P = ½ an q = ½
As per given question, when 10 coins are tossed , then probability 6 heads and 4 tails is =
10C6(p^6) (q)^(10–6)
= 10C6 / (2^10)
Now if the same activity is repeated 1000 times, then,
10c6×1000/1024
=205.08
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