Question

In how many different ways can 3 red balls, 2 blue balls and 4 yellow balls be arranged so that the balls of same colour come together ?

Answer 1

6 ways

1. RRRBBYYYY
2.BBRRRYYYY
3.RRRYYYYBB
4.BBYYYYRRR
5.YYYYBBRRR
6.YYYYRRRBB

Answer 2

Answer:

288 ways

Step-by-step explanation:

Given : 3 red balls, 2 blue balls and 4 yellow balls

To find : In how many different ways can 3 red balls, 2 blue balls and 4 yellow balls be arranged so that the balls of same color come together ?

Solution :

The ways in which 3 red balls come is = $3!$

The ways in which 2 blue balls come is =$2!$

The ways in which 4 yellow balls come is = $4!$

The ways in which 3 red balls , 2 blue balls and 4 yellow balls be arranged so that the balls of same color come together is

$=3!\times2!\times4!$

$=3\times2\times1\times2\times1\times4\times3\times2\times1$

$=6\times2\times24$

$=288$

Therefore, answer is 288 ways.