In how many different ways can the six faces of a cube be painted with six different colors
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This is a question on combination.
We have n = 6 (number of faces)
r = 6 (colours)
C = n! / r! (n - r)!
C = 6!/6!(6 - 6)!
C = 6! / 6!0!
C = 6!/6! = 1
The answer is one way.
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