Question

In how many different ways can you pay 117 rupees using 1,10 and 50 rupees

Answer 1

Answer:

18

Step-by-step explanation:

Let the number of currency in denominations of Rs. 1, Rs. 10 and Rs. 50 be x, y and z respectively.

Let the number of currency in denominations of Rs. 1, Rs. 10 and Rs. 50 be x, y and z respectively.x + 10y + 50z = 107

The possible values of z could be 0, 1 and 2.

he possible values of z could be 0, 1 and 2.For z = 0: x + 10y = 107

he possible values of z could be 0, 1 and 2.For z = 0: x + 10y = 107In this case, y can range from 0 to 10, so total 11 ways.

he possible values of z could be 0, 1 and 2.For z = 0: x + 10y = 107In this case, y can range from 0 to 10, so total 11 ways.For z = 1: x + 10y = 57

he possible values of z could be 0, 1 and 2.For z = 0: x + 10y = 107In this case, y can range from 0 to 10, so total 11 ways.For z = 1: x + 10y = 57In this case, y can range from 0 to 5, so total 6 ways.

he possible values of z could be 0, 1 and 2.For z = 0: x + 10y = 107In this case, y can range from 0 to 10, so total 11 ways.For z = 1: x + 10y = 57In this case, y can range from 0 to 5, so total 6 ways.For z = 2: x + 10y = 7

he possible values of z could be 0, 1 and 2.For z = 0: x + 10y = 107In this case, y can range from 0 to 10, so total 11 ways.For z = 1: x + 10y = 57In this case, y can range from 0 to 5, so total 6 ways.For z = 2: x + 10y = 7In this case, y can take only 1 value that is 0. that means there is only 1 way.

0. that means there is only 1 way.Total number of ways = 11 + 6 + 1 = 18