Question

in how many differnt ways
can 3 red balls 2 blue balls and 4 yellow balls can be arranged that no same color balls come togather

Answer 1

First arrange 4 yellow balls can arranged in 1 way.
In between, beginning and ending there are 5 places.
Arrange 3 red and 2 ball in those places in 5!/3!*2!=10 ways
Therefore total number of arrangements =1*10=10