in) How many moles of acetic anhydride will be required to form gloss
pentaacetate from 1 mole of glucose?
ii)
Answers
Answered by
9
Answer:
1)When acetylated with acetic anhydride (−O−
C
∥
O
−CH
3
), glucose forms a pentaacetate.
The reaction is as follows:
In the given reaction, 1M of glucose is producing glucose pentaacetate i.e. it contains 5 OAC group.
Therefore, 2M of glucose will produce glucose pentaacetate containing 10−OAC group.
Hence, 10 moles of acetic anhydride will be required to form glucose pentaacetate from 2M of glucose.
Answered by
1
Answer:
2
Explanation:
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