Chemistry, asked by superfrooti226, 2 months ago

In how many of the following compounds hybridization is not possible?
1) PC13
2) PH3
3) AsH3
4) H25
5) H2Se
6) PF3
7) N(SİH3)3
8) [XeF]

Answers

Answered by rajputarunsingh401
3

H25 is many of compounds hybridization because the compound will be high of getting so

Answered by Shazia055
1

(Here, it must be \[PC{l_3}\], \[{H_2}S\] and \[Xe{F_2}\] instead of PC13, H25 and [XeF].)

Among the following compounds, hybridisation is not possible in \[P{H_3},\,As{H_3},\,{H_2}S\] and \[{H_2}Se\].

Explanation:

  • According to Drago's rule, the elements of groups 15 and 16 from period 3 and below do not take part in hybridisation.
  • The bond angle in the compounds of those elements remains approximately \[90^\circ \].
  • Also, if the electronegativity of the combining elements are similar, in that also, the compound does not undergo hybridisation.
  • In \[P{H_3},\,As{H_3},\,{H_2}S\] and \[{H_2}Se\], no hybridisation tales place because the central atom in these compounds belongs to groups 15 and 16 and period 3 and below.
  • They have a bond angle around \[90^\circ \], also the electronegativity difference between the central atom and the hydrogen is not very high.
  • Therefore, they do not undergo hybridisation according to Drago's rule.
  • On the other hand, \[PC{l_3},\,P{F_3},\,N{(Si{H_3})_3}\] undergo \[s{p^3}\] hybridisation while \[Xe{F_2}\] undergoes \[s{p^3}d\] hybridisation.
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