in how many time will the simple interest on ₹8000 at 12 1/2% per annum be ₹ 250
Answers
Answer:
here is your answer:-
If person A borrows ₹8000 at 12% per annum simple interest and person B borrows ₹ 9100 at 10% per annum simple interest, in how many years will their amounts be equal?
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A and B owe the same amount after n years.
A pays 12% simple interest per year on 8000 rupees. Over n years, A will owe the original sum borrowed plus all the accrued interest:
A= 8000 + (8000 × 0.12 × n)
=8000+(960×n)
and,
B pays 10% simple interest per year on 9100 rupees. Over n years, B will similarly owe:
B= 9100 + (9100 × 0.10 × n)
=9100+(910×n)
so,
When will A and B owe the same?
Set A equal to B and solve for n
A=B
8000+(960×n)=9100+(910×n)
960n=1100+910n
50n=1100
n=22
ANSWER: A and B will equal after 22 years.
Hope it will help you
Answer:
the answer is 3 ok make the equation