Math, asked by kmrgamer24, 5 months ago

in how many time will the simple interest on ₹8000 at 12 1/2% per annum be ₹ 250​

Answers

Answered by veerjain25
3

Answer:

here is your answer:-

If person A borrows ₹8000 at 12% per annum simple interest and person B borrows ₹ 9100 at 10% per annum simple interest, in how many years will their amounts be equal?

Have questions related to property buy/sell or residential rent?

A and B owe the same amount after n years.

A pays 12% simple interest per year on 8000 rupees. Over n years, A will owe the original sum borrowed plus all the accrued interest:

A= 8000 + (8000 × 0.12 × n)

=8000+(960×n)

and,

B pays 10% simple interest per year on 9100 rupees. Over n years, B will similarly owe:

B= 9100 + (9100 × 0.10 × n)

=9100+(910×n)

so,

When will A and B owe the same?

Set A equal to B and solve for n

A=B

8000+(960×n)=9100+(910×n)

960n=1100+910n

50n=1100

n=22

ANSWER: A and B will equal after 22 years.

Hope it will help you

Answered by madhabiray9534
0

Answer:

the answer is 3 ok make the equation

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