Question

In how many ways 10 can seated in row such that a2 always sits before a5 and a5 always be before a7

Answer 1

Answer:

yes definitely

Step-by-step explanation:

is it right or wrong

Answer 2

Answer:

Number of ways in which a2​ is always above a5=10!/2​

Number of ways in which a5 is always above a7=10!/2​

Step-by-step explanation:

Total number of ways 10 can be seated = 10!

Number of ways in which a2​ is always above a5=10!/2​

Number of ways in which a5 is always above a7=10!/2​

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