Math, asked by zopemeenal2856, 11 months ago

In how many ways 3 leads can be selected out of 5 male and 4 females so that 1 female must be selected

Answers

Answered by priyanshubedi00
21

Answer:

74

Step-by-step explanation:

1) If 1 female is selected ,

No of ways to select female = 4C1 = 4

No. of ways to select male = 5C2 = 10

Required ways = 10×4 = 40

2) If 2 females are selected ,

No. of ways to select female = 4C2 = 6

No. of ways to select a male = 5C1 = 5

Required ways = 6×5 = 30

3) 3 females can be selected in 4C3 ways = 40 + 30 + 4 = 74

Total ways =

Answered by ksadarsh999
0

Answer:

Step-by-step explanation:

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