Math, asked by tapanpatel1818, 1 year ago

In how many ways 4 boys and 3 girls can be seated in a row so that they are alternate.
A.144
B.288
C.12
D.256

Answers

Answered by divyaraichura94
7

Answer:

288 optionb

Step-by-step explanation:

Since if boy get first seat there there will be4!×3! Ways and similarly if girl gets first place it will be also 4!×3!

Therefore answer is 2×4!×3! = 288

Answered by debrups71
0

Answer:

288

Step-by-step explanation:

2×3!×4!=288 1 and last has been occupied

Similar questions