in how many ways 6 books out of 10 different books can be arranged in a book shelf so 3 particular books are always together?
Answers
Answered by
3
Step-by-step explanation:
Total number of books = 10
No. of books fixed = 3
Remaining books = 7
To be selected = 3
No. of ways = 7P3
= 7!/4!
=7 × 6 × 5
= 210
Remaining three books arrange themselves in 3! = 6 ways
Total no. of ways = 210 × 6
= 1260
THANSK
Answered by
0
this is a problem of permutation and combination
210*24*6=30240
Similar questions